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TABLE 11-2 a Realtor Wants to Compare the Mean Sales-To-Appraisal Ratios of Ratios

Question 14

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TABLE 11-2
A realtor wants to compare the mean sales-to-appraisal ratios of residential properties sold in four neighborhoods (A,B,C,and D) .Four properties are randomly selected from each neighborhood and the ratios recorded for each,as shown below.
A: 1.2,1.1,0.9,0.4 C: 1.0,1.5,1.1,1.3
B: 2.5,2.1,1.9,1.6 D: 0.8,1.3,1.1,0.7
Interpret the results of the analysis summarized in the following table: TABLE 11-2 A realtor wants to compare the mean sales-to-appraisal ratios of residential properties sold in four neighborhoods (A,B,C,and D) .Four properties are randomly selected from each neighborhood and the ratios recorded for each,as shown below. A: 1.2,1.1,0.9,0.4 C: 1.0,1.5,1.1,1.3 B: 2.5,2.1,1.9,1.6 D: 0.8,1.3,1.1,0.7 Interpret the results of the analysis summarized in the following table: -Referring to Table 11-2,the null hypothesis for Levene's test for homogeneity of variances is A) H<sub>0</sub> : μ<sub>A</sub> = μ<sub>B</sub>= μ<sub>C</sub> = μ<sub>D</sub>. B) H<sub>0 </sub>: M<sub>A</sub> = M<sub>B </sub>= M<sub>C </sub>= M<sub>D</sub>. C) H<sub>0</sub> : = = = . D) H<sub>0</sub> : π<sub>A</sub> = π<sub>B </sub>= π<sub>C </sub>= π<sub>D</sub>.
-Referring to Table 11-2,the null hypothesis for Levene's test for homogeneity of variances is


A) H0 : μA = μB= μC = μD.
B) H0 : MA = MB = MC = MD.
C) H0 : TABLE 11-2 A realtor wants to compare the mean sales-to-appraisal ratios of residential properties sold in four neighborhoods (A,B,C,and D) .Four properties are randomly selected from each neighborhood and the ratios recorded for each,as shown below. A: 1.2,1.1,0.9,0.4 C: 1.0,1.5,1.1,1.3 B: 2.5,2.1,1.9,1.6 D: 0.8,1.3,1.1,0.7 Interpret the results of the analysis summarized in the following table: -Referring to Table 11-2,the null hypothesis for Levene's test for homogeneity of variances is A) H<sub>0</sub> : μ<sub>A</sub> = μ<sub>B</sub>= μ<sub>C</sub> = μ<sub>D</sub>. B) H<sub>0 </sub>: M<sub>A</sub> = M<sub>B </sub>= M<sub>C </sub>= M<sub>D</sub>. C) H<sub>0</sub> : = = = . D) H<sub>0</sub> : π<sub>A</sub> = π<sub>B </sub>= π<sub>C </sub>= π<sub>D</sub>. = TABLE 11-2 A realtor wants to compare the mean sales-to-appraisal ratios of residential properties sold in four neighborhoods (A,B,C,and D) .Four properties are randomly selected from each neighborhood and the ratios recorded for each,as shown below. A: 1.2,1.1,0.9,0.4 C: 1.0,1.5,1.1,1.3 B: 2.5,2.1,1.9,1.6 D: 0.8,1.3,1.1,0.7 Interpret the results of the analysis summarized in the following table: -Referring to Table 11-2,the null hypothesis for Levene's test for homogeneity of variances is A) H<sub>0</sub> : μ<sub>A</sub> = μ<sub>B</sub>= μ<sub>C</sub> = μ<sub>D</sub>. B) H<sub>0 </sub>: M<sub>A</sub> = M<sub>B </sub>= M<sub>C </sub>= M<sub>D</sub>. C) H<sub>0</sub> : = = = . D) H<sub>0</sub> : π<sub>A</sub> = π<sub>B </sub>= π<sub>C </sub>= π<sub>D</sub>. = TABLE 11-2 A realtor wants to compare the mean sales-to-appraisal ratios of residential properties sold in four neighborhoods (A,B,C,and D) .Four properties are randomly selected from each neighborhood and the ratios recorded for each,as shown below. A: 1.2,1.1,0.9,0.4 C: 1.0,1.5,1.1,1.3 B: 2.5,2.1,1.9,1.6 D: 0.8,1.3,1.1,0.7 Interpret the results of the analysis summarized in the following table: -Referring to Table 11-2,the null hypothesis for Levene's test for homogeneity of variances is A) H<sub>0</sub> : μ<sub>A</sub> = μ<sub>B</sub>= μ<sub>C</sub> = μ<sub>D</sub>. B) H<sub>0 </sub>: M<sub>A</sub> = M<sub>B </sub>= M<sub>C </sub>= M<sub>D</sub>. C) H<sub>0</sub> : = = = . D) H<sub>0</sub> : π<sub>A</sub> = π<sub>B </sub>= π<sub>C </sub>= π<sub>D</sub>. = TABLE 11-2 A realtor wants to compare the mean sales-to-appraisal ratios of residential properties sold in four neighborhoods (A,B,C,and D) .Four properties are randomly selected from each neighborhood and the ratios recorded for each,as shown below. A: 1.2,1.1,0.9,0.4 C: 1.0,1.5,1.1,1.3 B: 2.5,2.1,1.9,1.6 D: 0.8,1.3,1.1,0.7 Interpret the results of the analysis summarized in the following table: -Referring to Table 11-2,the null hypothesis for Levene's test for homogeneity of variances is A) H<sub>0</sub> : μ<sub>A</sub> = μ<sub>B</sub>= μ<sub>C</sub> = μ<sub>D</sub>. B) H<sub>0 </sub>: M<sub>A</sub> = M<sub>B </sub>= M<sub>C </sub>= M<sub>D</sub>. C) H<sub>0</sub> : = = = . D) H<sub>0</sub> : π<sub>A</sub> = π<sub>B </sub>= π<sub>C </sub>= π<sub>D</sub>. .
D) H0 : πA = πB = πC = πD.

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