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TABLE 11-8 An Important Factor in Selecting Database Software Is the Time

Question 34

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TABLE 11-8
An important factor in selecting database software is the time required for a user to learn how to use the system.To evaluate three potential brands (A,B and C) of database software,a company designed a test involving five different employees.To reduce variability due to differences among employees,each of the five employees is trained on each of the three different brands.The amount of time (in hours) needed to learn each of the three different brands is given below: TABLE 11-8 An important factor in selecting database software is the time required for a user to learn how to use the system.To evaluate three potential brands (A,B and C) of database software,a company designed a test involving five different employees.To reduce variability due to differences among employees,each of the five employees is trained on each of the three different brands.The amount of time (in hours) needed to learn each of the three different brands is given below: Below is the Excel output for the randomized block design: -Referring to Table 11-8,the null hypothesis for the randomized block F test for the difference in the means is A) H<sub>0 </sub>: μ<sub>A </sub>= μ<sub>B </sub>= μ<sub>C</sub> B) H<sub>0</sub> : μ<sub>1</sub> = μ<sub>2 </sub>= μ<sub>3</sub> = μ<sub>4 </sub>= μ<sub>5</sub> C) H<sub>0</sub> : M<sub>A </sub>= M<sub>B</sub> = M<sub>C</sub> D) H<sub>0</sub> : M<sub>1</sub> = M<sub>2</sub> = M<sub>3</sub> = M<sub>4</sub> = M<sub>5</sub> Below is the Excel output for the randomized block design: TABLE 11-8 An important factor in selecting database software is the time required for a user to learn how to use the system.To evaluate three potential brands (A,B and C) of database software,a company designed a test involving five different employees.To reduce variability due to differences among employees,each of the five employees is trained on each of the three different brands.The amount of time (in hours) needed to learn each of the three different brands is given below: Below is the Excel output for the randomized block design: -Referring to Table 11-8,the null hypothesis for the randomized block F test for the difference in the means is A) H<sub>0 </sub>: μ<sub>A </sub>= μ<sub>B </sub>= μ<sub>C</sub> B) H<sub>0</sub> : μ<sub>1</sub> = μ<sub>2 </sub>= μ<sub>3</sub> = μ<sub>4 </sub>= μ<sub>5</sub> C) H<sub>0</sub> : M<sub>A </sub>= M<sub>B</sub> = M<sub>C</sub> D) H<sub>0</sub> : M<sub>1</sub> = M<sub>2</sub> = M<sub>3</sub> = M<sub>4</sub> = M<sub>5</sub>
-Referring to Table 11-8,the null hypothesis for the randomized block F test for the difference in the means is


A) H0 : μA = μB = μC
B) H0 : μ1 = μ2 = μ3 = μ4 = μ5
C) H0 : MA = MB = MC
D) H0 : M1 = M2 = M3 = M4 = M5

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