To Estimate the Total Number of Successes in a Large $$\tilde { p } \pm z _ { \alpha / 2 } \sqrt { \tilde { p } ( 1 - \tilde { p } ) / n }$$

Multiple Choice

To estimate the total number of successes in a large finite population of size N,using a sample of size n,the confidence interval estimator is:

A) $$\tilde { p } \pm z _ { \alpha / 2 } \sqrt { \tilde { p } ( 1 - \tilde { p } ) / n }$$
B) $$N \left[ \tilde { p } \pm z _ { \alpha / 2 } \sqrt { \tilde { p } ( 1 - \tilde { p } ) / n } \right]$$
C) $$( N + n ) \left[ \tilde { p } \pm z _ { a / 2 } \sqrt { \tilde { p } ( 1 - \tilde { p } ) / n } \right]$$
D) $$( N - n ) \left[ \tilde { p } \pm z _ { \alpha / 2 } \sqrt { \tilde { p } ( 1 - \tilde { p } ) / n } \right]$$