Multiple Choice
Given that s is a String, what does the following loop do? for(int j = s.length() ; j > 0; j--)
System.out.print;
A) It prints s out backwards
B) It prints s out forwards
C) It prints s out backwards after skipping the last character
D) It prints s out backwards but does not print the first character
E) It yields a run-time error because there is no character at s.charAt(j-1) for j = 0
Correct Answer:

Verified
Correct Answer:
Verified
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