Given That,at 25°C, C(s)+ O 2 (g)→ CO 2 (g) ΔG° = −394$\frac{1}{2}$ O 2 (g)→ CO(g) ΔG° = −137

The Answer of Given That,at 25°C, C(s)+ O 2 (g)→ CO 2 (g) ΔG° = −394$\frac{1}{2}$ O 2 (g)→ CO(g) ΔG° = −137

Given That,at 25°C, C(s)+ O 2 (g)→ CO 2 (g) ΔG° = −394$\frac{1}{2}$ O 2 (g)→ CO(g) ΔG° = −137

The Answer of Given That,at 25°C, C(s)+ O 2 (g)→ CO 2 (g) ΔG° = −394$\frac{1}{2}$ O 2 (g)→ CO(g) ΔG° = −137

Solved

Given That,at 25°C, C(s)+ O₂(g)→ CO₂(g)
ΔG° = −394 $\frac{1}{2}$ O₂(g)→ CO(g)
ΔG° = −137

Question 35

Multiple Choice

Given that,at 25°C, C(s) + O₂(g) → CO₂(g)
ΔG° = −394.4 kJ
C(s) + $\frac{1}{2}$ O₂(g) → CO(g)
ΔG° = −137.2 kJ
Calculate ΔG° for the reaction below.
CO(g) + $\frac{1}{2}$ O₂(g) → CO₂(g)

A) −531.6 kJ
B) −257.2 kJ
C) −171.5 kJ
D) +141.2 kJ
E) +531.6 kJ

Given That,at 25°C, C(s)+ O2(g)→ CO2(g) ΔG° = −394 12\frac{1}{2}21​ O2(g)→ CO(g) ΔG° = −137

Multiple Choice

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Given That,at 25°C, C(s)+ O₂(g)→ CO₂(g)
ΔG° = −394 $\frac{1}{2}$ O₂(g)→ CO(g)
ΔG° = −137

Correct Answer:
Verified
Unlock this answer now
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