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    Chemistry and Chemical Reactivity
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    Exam 12: Intermolecular Forces and Liquids
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    Arrange H<sub>2</sub>S,H<sub>2</sub>Se,and H<sub>2</sub>Te in Order from Lowest to Highest Boiling
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Arrange H2S,H2Se,and H2Te in Order from Lowest to Highest Boiling

Question 56

Question 56

Multiple Choice

Arrange H2S,H2Se,and H2Te in order from lowest to highest boiling point.


A) H2Te < H2Se < H2S
B) H2S < H2Se < H2Te
C) H2S < H2Te < H2Se
D) H2Se < H2Te < H2S
E) H2Te < H2S < H2Se

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