Solved

The Graph in Figure 17-18 Shows the Time Course of the Polymerization

Question 23

Multiple Choice

The graph in Figure 17-18 shows the time course of the polymerization of pure tubulin in vitro.Assume that the starting concentration of free tubulin is higher than it is in cells. The graph in Figure 17-18 shows the time course of the polymerization of pure tubulin in vitro.Assume that the starting concentration of free tubulin is higher than it is in cells.   Figure 17-18 Three parts of the curve are labeled above it as A, B, and C.You conduct a similar in vitro tubulin-polymerization experiment, only this time you include purified centrosomes in your preparation.When you plot your data, which part of your graph should be most dissimilar to the curve shown in Figure 17-18? A) A B) B C) C D) None.The shape of my graph should be identical to the graph produced when tubulin is polymerized in the absence of purified centrosomes. Figure 17-18
Three parts of the curve are labeled above it as A, B, and C.You conduct a similar in vitro tubulin-polymerization experiment, only this time you include purified centrosomes in your preparation.When you plot your data, which part of your graph should be most dissimilar to the curve shown in Figure 17-18?


A) A
B) B
C) C
D) None.The shape of my graph should be identical to the graph produced when tubulin is polymerized in the absence of purified centrosomes.

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions