Answer True or False $\varepsilon$ When 0 < |X - A|

True/False

Answer true or false. It can be shown that if |f(x) - L| < $\varepsilon$ when 0 < |x - a| < $\delta$ , then |x² - 9| < $\varepsilon$ if |x - 3| < $\delta$ for arbitrarily small positive $\varepsilon$ .