The Reaction of 50 ML of Cl₂ gas with 50

Multiple Choice

The reaction of 50 mL of Cl₂ gas with 50 mL of CH₄ gas via the equation:
Cl₂ (g) + CH₄ (g) - HCl (g) + CH₃Cl (g)
Will produce a total of mL of products if pressure and temperature are kept constant.

A) 150
B) 250
C) 100
D) 200
E) 50