Solved

The Probabilities Shown in a Table with Two Rows

Question 55

Multiple Choice

The probabilities shown in a table with two rows, The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. and The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. and two columns, The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. and The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. ,are as follows: P( The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. and The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. ) = 0.10,P( The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. and The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. ) = 0.30,P( The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. and The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. ) = 0.05,and P( The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. and The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. ) = 0.55.Then P( The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. | The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and ) = 0.10,P( and ) = 0.30,P( and ) = 0.05,and P( and ) = 0.55.Then P( | ) ,calculated up to two decimals,is A) 0.33. B) 0.35. C) 0.65. D) 0.67. ) ,calculated up to two decimals,is


A) 0.33.
B) 0.35.
C) 0.65.
D) 0.67.

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Q45: The Poisson distribution is applied to events

Q50: ​A probability tree is a graphical representation

Q52: The binomial random variable represents the number

Q53: According to the empirical rule,how many observations

Q54: What is the probability that GM will

Q56: The Poisson distribution is characterized by a

Q57: Two events A and B are said

Q58: Find the expected demand (in units)for the

Q59: If two events are independent,what is the

Q60: Find the mean and the variance of