The probabilities shown in a table with two rows,

and

and two columns, The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and )= 0.10,P( and )= 0.30,P( and )= 0.05,and P( and )= 0.55.Then P( | )is A)0.33. B)0.35. C)0.65. D)0.67.

and

,are as follows: P( The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and )= 0.10,P( and )= 0.30,P( and )= 0.05,and P( and )= 0.55.Then P( | )is A)0.33. B)0.35. C)0.65. D)0.67.

and

)= 0.10,P( The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and )= 0.10,P( and )= 0.30,P( and )= 0.05,and P( and )= 0.55.Then P( | )is A)0.33. B)0.35. C)0.65. D)0.67.

and

)= 0.30,P( The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and )= 0.10,P( and )= 0.30,P( and )= 0.05,and P( and )= 0.55.Then P( | )is A)0.33. B)0.35. C)0.65. D)0.67.

and

)= 0.05,and P( The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and )= 0.10,P( and )= 0.30,P( and )= 0.05,and P( and )= 0.55.Then P( | )is A)0.33. B)0.35. C)0.65. D)0.67.

and

)= 0.55.Then P( The probabilities shown in a table with two rows, and and two columns, and ,are as follows: P( and )= 0.10,P( and )= 0.30,P( and )= 0.05,and P( and )= 0.55.Then P( | )is A)0.33. B)0.35. C)0.65. D)0.67.

)is
A)0.33.
B)0.35.
C)0.65.
D)0.67.

Sampling Done Without Replacement Means That

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