The average speed of oxygen molecules at 570°C is 1.49 × 10⁵ cm/s. Which of the following calculations would convert this speed to units of miles per hour?
A)

\frac { 1 \mathrm {~s} } { 1.49 \times 10 ^ { 5 } } \times \frac { 2.54 \mathrm {~cm} } { 1 \mathrm { in } } \times \frac { 1 \mathrm { ft } } { 12 \mathrm { in } } \times \frac { 1 \mathrm { mi } } { 5280 \mathrm { ft } } \times \frac { 3600 \mathrm {~s} } { 1 \mathrm {~h} }

\frac { 1.49 \times 10 ^ { 5 } } { 1 \mathrm {~s} } \times \frac { 1 \mathrm { in } } { 2.54 \mathrm {~cm} } \times \frac { 12 \mathrm { in } } { 1 \mathrm { ft } } \times \frac { 5280 \mathrm { ft } } { 1 \mathrm { mi } } \times \frac { 1 \mathrm {~h} } { 3600 \mathrm {~s} }

\frac { 1.49 \times 10 ^ { 5 } } { 1 \mathrm {~s} } \times \frac { 1 \mathrm { in } } { 2.54 \mathrm {~cm} } \times \frac { 1 \mathrm { ft } } { 12 \mathrm { in } } \times \frac { 1 \mathrm { mi } } { 5280 \mathrm { ft } } \times \frac { 3600 \mathrm {~s} } { 1 \mathrm {~h} }

\frac { 1.49 \times 10 ^ { 5 } } { 1 \mathrm {~s} } \times \frac { 2.54 \mathrm {~cm} } { 1 \mathrm { in } } \times \frac { 12 \mathrm { in } } { 1 \mathrm { ft } } \times \frac { 5280 \mathrm { ft } } { 1 \mathrm { mi } } \times \frac { 3600 \mathrm {~s} } { 1 \mathrm {~h} }

\frac { 1 \mathrm {~s} } { 1.49 \times 10 ^ { 5 } } \times \frac { 2.54 \mathrm {~cm} } { 1 \mathrm { in } } \times \frac { 12 \mathrm { in } } { 1 \mathrm { ft } } \times \frac { 5280 \mathrm { ft } } { 1 \mathrm { mi } } \times \frac { 1 \mathrm {~h} } { 3600 \mathrm {~s} }

Order the Four Metric Units Provided from Smallest to Largest

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