Multiple Choice
Consider the minimumPosition method from the SelectionSorter class. Complete the code to write a maximumPosition method that returns the index of the largest element in the range from index from to the end of the array. private static int minimumPosition(int[] a, int from)
{
Int minPos = from;
For (int i = from + 1; i < a.length; i++)
{
If (a[i] < a[minPos]) { minPos = i; }
}
Return minPos;
}
Private static int maximumPosition(int[] a, int from)
{
Int maxPos = from;
For (int i = from + 1; i < a.length; i++)
{
________________
}
Return maxPos;
}
A) if(a[i] > a[maxPos]) { maxPos = i; }
B) if(a[i] == a[maxPos]) { maxPos = i; }
C) if(a[i] < a[maxPos]) { maxPos = i; }
D) if(a[i] <= a[maxPos]) { maxPos = i; }
Correct Answer:

Verified
Correct Answer:
Verified
Q43: A version of which sort algorithm is
Q44: A portion of your program includes the
Q45: Consider an array with n elements. If
Q46: Which sort algorithm starts by cutting the
Q47: In big-Oh notation, when we consider the
Q49: If an element is present in an
Q50: Assume that bands is an ArrayList of
Q51: Find the simplest order of growth of
Q52: If you increase the size of a
Q53: After 5 iterations of selection sort working