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A Circular Loop of Diameter 10 Cm, Carrying a Current

Question 38

Multiple Choice

A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field = 0.30 T . The normal to the loop is parallel to a unit vector = -0.60 - 0.80 . Calculate the magnitude of the torque on the loop due to the magnetic field. A) 4.7 × 10<sup>-4</sup> N ∙ m B) 2.8 × 10<sup>-4</sup> N ∙ m C) 0.60 × 10<sup>-4</sup> N ∙ m D) 1.2 × 10<sup>-4</sup> N ∙ m E) zero = 0.30 T A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field = 0.30 T . The normal to the loop is parallel to a unit vector = -0.60 - 0.80 . Calculate the magnitude of the torque on the loop due to the magnetic field. A) 4.7 × 10<sup>-4</sup> N ∙ m B) 2.8 × 10<sup>-4</sup> N ∙ m C) 0.60 × 10<sup>-4</sup> N ∙ m D) 1.2 × 10<sup>-4</sup> N ∙ m E) zero . The normal to the loop is parallel to a unit vector A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field = 0.30 T . The normal to the loop is parallel to a unit vector = -0.60 - 0.80 . Calculate the magnitude of the torque on the loop due to the magnetic field. A) 4.7 × 10<sup>-4</sup> N ∙ m B) 2.8 × 10<sup>-4</sup> N ∙ m C) 0.60 × 10<sup>-4</sup> N ∙ m D) 1.2 × 10<sup>-4</sup> N ∙ m E) zero = -0.60 A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field = 0.30 T . The normal to the loop is parallel to a unit vector = -0.60 - 0.80 . Calculate the magnitude of the torque on the loop due to the magnetic field. A) 4.7 × 10<sup>-4</sup> N ∙ m B) 2.8 × 10<sup>-4</sup> N ∙ m C) 0.60 × 10<sup>-4</sup> N ∙ m D) 1.2 × 10<sup>-4</sup> N ∙ m E) zero - 0.80 A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field = 0.30 T . The normal to the loop is parallel to a unit vector = -0.60 - 0.80 . Calculate the magnitude of the torque on the loop due to the magnetic field. A) 4.7 × 10<sup>-4</sup> N ∙ m B) 2.8 × 10<sup>-4</sup> N ∙ m C) 0.60 × 10<sup>-4</sup> N ∙ m D) 1.2 × 10<sup>-4</sup> N ∙ m E) zero . Calculate the magnitude of the torque on the loop due to the magnetic field.


A) 4.7 × 10-4 N ∙ m
B) 2.8 × 10-4 N ∙ m
C) 0.60 × 10-4 N ∙ m
D) 1.2 × 10-4 N ∙ m
E) zero

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