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The Following Is a System of Simultaneous Linear Equations to Allocate

Question 2

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The following is a system of simultaneous linear equations to allocate costs using the reciprocal method. Matrix algebra is not required.
The following costs were incurred in three operating departments and three service departments in Westmoreland Company.
 Department  Direct Costs  Label  Subassemblies $550,000 P1  Final assembly 775,000 P2  Marketing 285,000 P3  Building occupancy 85,000S 1  Research & development 120,000S2  Supervision 45,000S 3 \begin{array} { l c c } \text { Department } & \text { Direct Costs } & \text { Label } \\\text { Subassemblies } & \$ { 5 5 0 , 0 0 0 } & \text { P1 } \\\text { Final assembly } & 775,000 & \text { P2 } \\\text { Marketing } & 285,000 & \text { P3 } \\\text { Building occupancy } & 85,000 & \text {S 1 } \\\text { Research \& development } & 120,000 & \text {S2 } \\\text { Supervision } & 45,000 & \text {S 3 }\end{array}
Use of services by other departments is as follows.
 The following is a system of simultaneous linear equations to allocate costs using the reciprocal method. Matrix algebra is not required. The following costs were incurred in three operating departments and three service departments in Westmoreland Company.  \begin{array} { l c c }  \text { Department } & \text { Direct Costs } & \text { Label } \\ \text { Subassemblies } & \$ { 5 5 0 , 0 0 0 } & \text { P1 } \\ \text { Final assembly } & 775,000 & \text { P2 } \\ \text { Marketing } & 285,000 & \text { P3 } \\ \text { Building occupancy } & 85,000 &  \text {S 1 } \\ \text { Research \& development } & 120,000 &  \text {S2 } \\ \text { Supervision } & 45,000 & \text {S 3 } \end{array}  Use of services by other departments is as follows.   - The equation for department S2 (research and development)  is: A)  S2 = $120,000 + 0.15S1 + 0.65S2 + 0.20S3. B)  S2 = 0.15S1 + 20S3. C)  S2 = $120,000 + 0.15S1 + 0.20S3. D)  S2 = $120,000 + 0.40S1 + 0.60S3.
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The equation for department S2 (research and development) is:


A) S2 = $120,000 + 0.15S1 + 0.65S2 + 0.20S3.
B) S2 = 0.15S1 + 20S3.
C) S2 = $120,000 + 0.15S1 + 0.20S3.
D) S2 = $120,000 + 0.40S1 + 0.60S3.

Correct Answer:

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