A Bacterium of Genotype A⁺b⁺c⁺d⁺ Is the Donor in a Cotransformation

Multiple Choice

A bacterium of genotype a⁺b⁺c⁺d⁺ is the donor in a cotransformation mapping. The recipient is a^-b^-c^-d^-. Data from the transformed cells (genotype and percent of each cotransformant) are shown below. What is the order of the genes? $$\begin{array} { l c } \text { Genotype } & \text { Cotransformants } \\a ^ { + } \text {and } b ^ { + } & 2 \% \\a ^ { + } \text {and } c ^ { + } & 0 \% \\a ^ { + } \text {and } d ^ { + } & 5 \% \\b ^ { + } \text {and } c ^ { + } & 5 \% \\b ^ { + } \text {and } a ^ { + } & 0 \% \\c ^ { + } \text {and } d ^ { + } & 0 \%\end{array}$$

A) a c b d
B) a d c b
C) c b a d
D) c a d b
E) b c d a