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Write the Standard Form of the Equation of the Circle (x+3)2+(y6)2=8( x + 3 ) ^ { 2 } + ( y - 6 ) ^ { 2 } = \sqrt { 8 }

Question 387

Multiple Choice

Write the standard form of the equation of the circle which has (-5, 4) and (-1, 8) as endpoints of a diameter.


A) (x+3) 2+(y6) 2=8( x + 3 ) ^ { 2 } + ( y - 6 ) ^ { 2 } = \sqrt { 8 }
B) (x3) 2+(y+6) 2=8( x - 3 ) ^ { 2 } + ( y + 6 ) ^ { 2 } = 8
C) (x3) 2+(y6) 2=8( x - 3 ) ^ { 2 } + ( y - 6 ) ^ { 2 } = 8
D) (x3) 2+(y6) 2=8( x - 3 ) ^ { 2 } + ( y - 6 ) ^ { 2 } = \sqrt { 8 }
E) (x+3) 2+(y6) 2=8( x + 3 ) ^ { 2 } + ( y - 6 ) ^ { 2 } = 8

Correct Answer:

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