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The Function f(x)=x25f ( x ) = x ^ { 2 } - 5

Question 243

Multiple Choice

The function f(x) =x25f ( x ) = x ^ { 2 } - 5 is one-to-one on the domain (x0) ( x \leq 0 ) .Find f1(x) f ^ { - 1 } ( x ) .


A) f1(x) =x2+5f ^ { - 1 } ( x ) = x ^ { 2 } + 5
B) f1(x) =x+5f ^ { - 1 } ( x ) = \sqrt { x + 5 }
C) f1(x) =x+5f ^ { - 1 } ( x ) = - \sqrt { x + 5 }
D) f1(x) =1x25f ^ { - 1 } ( x ) = \frac { 1 } { x ^ { 2 } - 5 }
E) f1(x) =x5f ^ { - 1 } ( x ) = \sqrt { x - 5 }

Correct Answer:

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