Evaluate (if possible) the sine, cosine, and tangent of the real number.

t = \frac { 25 \pi } { 3 }

t = \frac { 25 \pi } { 3 }

corresponds to the point

( x , y ) = \left( \frac { 1 } { 2 } , \frac { \sqrt { 3 } } { 2 } \right)

\begin{array} { l } \sin \left( \frac { 25 \pi } { 3 } \right) = - \frac { 1 } { 2 } \\\cos \left( \frac { 25 \pi } { 3 } \right) = \frac { \sqrt { 3 } } { 2 } \\\tan \left( \frac { 25 \pi } { 3 } \right) = - \sqrt { 3 }\end{array}

t = \frac { 25 \pi } { 3 }

corresponds to the point

( x , y ) = \left( \frac { 1 } { 2 } , \frac { \sqrt { 3 } } { 2 } \right)

\begin{array} { l } \sin \left( \frac { 25 \pi } { 3 } \right) = \frac { \sqrt { 3 } } { 2 } \\\cos \left( \frac { 25 \pi } { 3 } \right) = \frac { 1 } { 2 } \\\tan \left( \frac { 25 \pi } { 3 } \right) = \sqrt { 3 }\end{array}

t = \frac { 25 \pi } { 3 }

corresponds to the point

( x , y ) = \left( - \frac { 1 } { 2 } , - \frac { \sqrt { 3 } } { 2 } \right)

\begin{array} { l } \sin \left( \frac { 25 \pi } { 3 } \right) = - \frac { 1 } { 2 } \\\cos \left( \frac { 25 \pi } { 3 } \right) = - \frac { \sqrt { 3 } } { 2 } \\\tan \left( \frac { 25 \pi } { 3 } \right) = \frac { \sqrt { 3 } } { 3 }\end{array}

t = \frac { 25 \pi } { 3 }

corresponds to the point

( x , y ) = \left( \frac { 1 } { 2 } , - \frac { \sqrt { 3 } } { 2 } \right)

\begin{array} { l } \sin \left( \frac { 25 \pi } { 3 } \right) = - \frac { 1 } { 2 } \\\cos \left( \frac { 25 \pi } { 3 } \right) = \frac { \sqrt { 3 } } { 2 } \\\tan \left( \frac { 25 \pi } { 3 } \right) = - \frac { \sqrt { 3 } } { 3 }\end{array}

E)Not possible

For the Simple Harmonic Motion Described by the Trigonometric Function d=112sin⁡14πtd = \frac { 1 } { 12 } \sin 14 \pi td=121​sin14πt

Multiple Choice