Select a right triangle corresponding to the trigonometric function of the acute angle

\theta

.Use the Pythagorean Theorem to determine the third side and then find the other five trigonometric functions of

\theta

.
Tan

\theta

\frac { 5 } { 12 }

Sin

\theta

\frac { 5 } { 13 }

csc

\theta

\frac { 13 } { 5 }

cos

\theta

\frac { 12 } { 13 }

sec

\theta

\frac { 13 } { 12 }

tan

\theta

\frac { 5 } { 12 }

cot

\theta

\frac { 12 } { 5 }

A) $Select a right triangle corresponding to the trigonometric function of the acute angle \theta .Use the Pythagorean Theorem to determine the third side and then find the other five trigonometric functions of \theta . Tan \theta = \frac { 5 } { 12 } Sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } A) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } B) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 12 } { 5 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 13 } { 12 } C) sin \theta = \frac { 13 } { 12 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 5 } sec \theta = \frac { 5 } { 13 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 13 } D) sin \theta = \frac { 13 } { 5 } csc \theta = \frac { 5 } { 13 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 12 } { 5 } cot \theta = \frac { 5 } { 12 } E) sin \theta = \frac { 12 } { 5 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 5 } { 13 }$ sin

\theta

\frac { 5 } { 13 }

csc

\theta

\frac { 13 } { 5 }

cos

\theta

\frac { 12 } { 13 }

sec

\theta

\frac { 13 } { 12 }

tan

\theta

\frac { 5 } { 12 }

cot

\theta

\frac { 12 } { 5 }

B) $Select a right triangle corresponding to the trigonometric function of the acute angle \theta .Use the Pythagorean Theorem to determine the third side and then find the other five trigonometric functions of \theta . Tan \theta = \frac { 5 } { 12 } Sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } A) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } B) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 12 } { 5 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 13 } { 12 } C) sin \theta = \frac { 13 } { 12 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 5 } sec \theta = \frac { 5 } { 13 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 13 } D) sin \theta = \frac { 13 } { 5 } csc \theta = \frac { 5 } { 13 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 12 } { 5 } cot \theta = \frac { 5 } { 12 } E) sin \theta = \frac { 12 } { 5 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 5 } { 13 }$ sin

\theta

\frac { 5 } { 13 }

csc

\theta

\frac { 5 } { 12 }

cos

\theta

\frac { 12 } { 13 }

sec

\theta

\frac { 12 } { 5 }

tan

\theta

\frac { 13 } { 5 }

cot

\theta

\frac { 13 } { 12 }

C) $Select a right triangle corresponding to the trigonometric function of the acute angle \theta .Use the Pythagorean Theorem to determine the third side and then find the other five trigonometric functions of \theta . Tan \theta = \frac { 5 } { 12 } Sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } A) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } B) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 12 } { 5 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 13 } { 12 } C) sin \theta = \frac { 13 } { 12 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 5 } sec \theta = \frac { 5 } { 13 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 13 } D) sin \theta = \frac { 13 } { 5 } csc \theta = \frac { 5 } { 13 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 12 } { 5 } cot \theta = \frac { 5 } { 12 } E) sin \theta = \frac { 12 } { 5 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 5 } { 13 }$ sin

\theta

\frac { 13 } { 12 }

csc

\theta

\frac { 13 } { 5 }

cos

\theta

\frac { 12 } { 5 }

sec

\theta

\frac { 5 } { 13 }

tan

\theta

\frac { 5 } { 12 }

cot

\theta

\frac { 12 } { 13 }

D) $Select a right triangle corresponding to the trigonometric function of the acute angle \theta .Use the Pythagorean Theorem to determine the third side and then find the other five trigonometric functions of \theta . Tan \theta = \frac { 5 } { 12 } Sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } A) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } B) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 12 } { 5 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 13 } { 12 } C) sin \theta = \frac { 13 } { 12 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 5 } sec \theta = \frac { 5 } { 13 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 13 } D) sin \theta = \frac { 13 } { 5 } csc \theta = \frac { 5 } { 13 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 12 } { 5 } cot \theta = \frac { 5 } { 12 } E) sin \theta = \frac { 12 } { 5 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 5 } { 13 }$ sin

\theta

\frac { 13 } { 5 }

csc

\theta

\frac { 5 } { 13 }

cos

\theta

\frac { 13 } { 12 }

sec

\theta

\frac { 12 } { 13 }

tan

\theta

\frac { 12 } { 5 }

cot

\theta

\frac { 5 } { 12 }

E) $Select a right triangle corresponding to the trigonometric function of the acute angle \theta .Use the Pythagorean Theorem to determine the third side and then find the other five trigonometric functions of \theta . Tan \theta = \frac { 5 } { 12 } Sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } A) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } B) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 12 } { 5 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 13 } { 12 } C) sin \theta = \frac { 13 } { 12 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 5 } sec \theta = \frac { 5 } { 13 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 13 } D) sin \theta = \frac { 13 } { 5 } csc \theta = \frac { 5 } { 13 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 12 } { 5 } cot \theta = \frac { 5 } { 12 } E) sin \theta = \frac { 12 } { 5 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 5 } { 13 }$ sin

\theta

\frac { 12 } { 5 }

csc

\theta

\frac { 5 } { 12 }

cos

\theta

\frac { 13 } { 12 }

sec

\theta

\frac { 12 } { 13 }

tan

\theta

\frac { 13 } { 5 }

cot

\theta

\frac { 5 } { 13 }

For the Simple Harmonic Motion Described by the Trigonometric Function d=6cos⁡6π5td = 6 \cos \frac { 6 \pi } { 5 } td=6cos56π​t

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For the Simple Harmonic Motion Described by the Trigonometric Function $d = 6 \cos \frac { 6 \pi } { 5 } t$

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