Evaluate (if possible) the sine, cosine, and tangent of the real number.

t = \frac { 25 \pi } { 3 }

t = \frac { 25 \pi } { 3 }

corresponds to the point

( x , y ) = \left( \frac { 1 } { 2 } , \frac { \sqrt { 3 } } { 2 } \right)

\begin{array} { l } \sin \left( \frac { 25 \pi } { 3 } \right) = - \frac { 1 } { 2 } \\\cos \left( \frac { 25 \pi } { 3 } \right) = \frac { \sqrt { 3 } } { 2 } \\\tan \left( \frac { 25 \pi } { 3 } \right) = - \sqrt { 3 }\end{array}

t = \frac { 25 \pi } { 3 }

corresponds to the point

( x , y ) = \left( \frac { 1 } { 2 } , \frac { \sqrt { 3 } } { 2 } \right)

\begin{array} { l } \sin \left( \frac { 25 \pi } { 3 } \right) = \frac { \sqrt { 3 } } { 2 } \\\cos \left( \frac { 25 \pi } { 3 } \right) = \frac { 1 } { 2 } \\\tan \left( \frac { 25 \pi } { 3 } \right) = \sqrt { 3 }\end{array}

t = \frac { 25 \pi } { 3 }

corresponds to the point

( x , y ) = \left( - \frac { 1 } { 2 } , - \frac { \sqrt { 3 } } { 2 } \right)

\begin{array} { l } \sin \left( \frac { 25 \pi } { 3 } \right) = - \frac { 1 } { 2 } \\\cos \left( \frac { 25 \pi } { 3 } \right) = - \frac { \sqrt { 3 } } { 2 } \\\tan \left( \frac { 25 \pi } { 3 } \right) = \frac { \sqrt { 3 } } { 3 }\end{array}

t = \frac { 25 \pi } { 3 }

corresponds to the point

( x , y ) = \left( \frac { 1 } { 2 } , - \frac { \sqrt { 3 } } { 2 } \right)

\begin{array} { l } \sin \left( \frac { 25 \pi } { 3 } \right) = - \frac { 1 } { 2 } \\\cos \left( \frac { 25 \pi } { 3 } \right) = \frac { \sqrt { 3 } } { 2 } \\\tan \left( \frac { 25 \pi } { 3 } \right) = - \frac { \sqrt { 3 } } { 3 }\end{array}

E)Not possible

Describe the Behavior of the Function Below as X Approaches f(x)=3cot⁡xf ( x ) = 3 \cot xf(x)=3cotx

Multiple Choice