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Use the Given Values to Evaluate (If Possible) Three Trigonometric secx=3,sinx=63\sec x = \sqrt { 3 } , \sin x = - \frac { \sqrt { 6 } } { 3 }

Question 169

Multiple Choice

Use the given values to evaluate (if possible) three trigonometric functions cos x, csc x, tan x.
secx=3,sinx=63\sec x = \sqrt { 3 } , \sin x = - \frac { \sqrt { 6 } } { 3 }


A) cosx=33cscx=62\begin{array} { l } \cos x = \frac { \sqrt { 3 } } { 3 } \\\csc x = - \frac { \sqrt { 6 } } { 2 }\end{array} tan x = - 2\sqrt { 2 }
B) cosx=33cscx=62\begin{array} { l } \cos x = - \frac { \sqrt { 3 } } { 3 } \\\csc x = - \frac { \sqrt { 6 } } { 2 }\end{array} tan x = - 2\sqrt { 2 }
C) cosx=66cscx=62\begin{array} { l } \cos x = \frac { \sqrt { 6 } } { 6 } \\\csc x = \frac { \sqrt { 6 } } { 2 }\end{array} tan x = 2\sqrt { 2 }
D) cosx=33cscx=62\begin{array} { l } \cos x = \frac { \sqrt { 3 } } { 3 } \\\csc x = - \frac { \sqrt { 6 } } { 2 }\end{array} tan x = 2\sqrt { 2 }
E) cosx=66cscx=62\begin{array} { l } \cos x = \frac { \sqrt { 6 } } { 6 } \\\csc x = \frac { \sqrt { 6 } } { 2 }\end{array} tan x = - 2\sqrt { 2 }

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