Use the Matrix Capabilities of a Graphing Utility to Solve $$\left\{ \begin{array} { c c c } 15 x - 5 y & = & 3 \\10 x + 10 y & = & 6 \\20 z & = & - 12\end{array} \right.$$

Multiple Choice

Use the matrix capabilities of a graphing utility to solve the following system of linear equations: $$\left\{ \begin{array} { c c c } 15 x - 5 y & = & 3 \\10 x + 10 y & = & 6 \\20 z & = & - 12\end{array} \right.$$

A) $\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 3 } { 10 } \\\frac { 9 } { 10 } \\\frac { - 3 } { 5 }\end{array} \right]$
B) $\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 9 } { 10 } \\0 \\\frac { - 3 } { 5 }\end{array} \right]$
C) $\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { - 3 } { 10 } \\\frac { 3 } { 10 } \\\frac { - 3 } { 5 }\end{array} \right]$
D) $\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 3 } { 10 } \\\frac { - 3 } { 10 } \\0\end{array} \right]$
E) $\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 3 } { 10 } \\\frac { 3 } { 10 } \\\frac { - 3 } { 5 }\end{array} \right]$