Find Pk _{+ 1} for the Given Pk $p _ { k } = \frac { 1 } { 4 ( k + 2 ) }$

Multiple Choice

Find pk _{+ 1} for the given pk. $p _ { k } = \frac { 1 } { 4 ( k + 2 ) }$

A) $p _ { k + 1 } = \frac { 1 } { k ( k + 3 ) }$
B) $p _ { k + 1 } = \frac { 4 } { ( k + 1 ) ( k + 2 ) }$
C) $p _ { k + 1 } = \frac { 4 } { k ( k + 3 ) }$
D) $p _ { k + 1 } = \frac { 1 } { ( k + 3 ) ( k + 2 ) }$
E) $p _ { k + 1 } = \frac { 1 } { 4 ( k + 3 ) }$