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Find Pk + 1 for the Given Pk pk=k5(8k+1)p _ { k } = \frac { k } { 5 } ( 8 k + 1 )

Question 16

Multiple Choice

Find pk + 1 for the given pk. pk=k5(8k+1) p _ { k } = \frac { k } { 5 } ( 8 k + 1 )


A) pk+1=k+15(8k+5) p _ { k + 1 } = \frac { k + 1 } { 5 } ( 8 k + 5 )
B) pk+1=k+15(8k+6) p _ { k + 1 } = \frac { k + 1 } { 5 } ( 8 k + 6 )
C) pk+1=k+16(8k+6) p _ { k + 1 } = \frac { k + 1 } { 6 } ( 8 k + 6 )
D) pk+1=k+15(8k+9) p _ { k + 1 } = \frac { k + 1 } { 5 } ( 8 k + 9 )
E) pk+1=k+16(8k+9) p _ { k + 1 } = \frac { k + 1 } { 6 } ( 8 k + 9 )

Correct Answer:

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