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By Using a Graphing Utility Select the Correct Graph of the Polar

Question 463

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By using a graphing utility select the correct graph of the polar equation.Identify the graph. 1313+16sinθ\frac { 13 } { 13 + 16 \sin \theta }


A)  By using a graphing utility select the correct graph of the polar equation.Identify the graph.   \frac { 13 } { 13 + 16 \sin \theta }   A)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola B)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola C)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola D)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola E)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola e=e = 1613\frac { 16 } { 13 } >1> 1 \Rightarrow Hyperbola
B)  By using a graphing utility select the correct graph of the polar equation.Identify the graph.   \frac { 13 } { 13 + 16 \sin \theta }   A)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola B)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola C)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola D)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola E)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola e=e = 1613\frac { 16 } { 13 } >1> 1 \Rightarrow Hyperbola
C)  By using a graphing utility select the correct graph of the polar equation.Identify the graph.   \frac { 13 } { 13 + 16 \sin \theta }   A)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola B)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola C)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola D)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola E)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola e=e = 1613\frac { 16 } { 13 } >1> 1 \Rightarrow Hyperbola
D)  By using a graphing utility select the correct graph of the polar equation.Identify the graph.   \frac { 13 } { 13 + 16 \sin \theta }   A)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola B)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola C)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola D)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola E)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola e=e = 1613\frac { 16 } { 13 } >1> 1 \Rightarrow Hyperbola
E)  By using a graphing utility select the correct graph of the polar equation.Identify the graph.   \frac { 13 } { 13 + 16 \sin \theta }   A)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola B)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola C)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola D)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola E)     e =   \frac { 16 } { 13 }   > 1 \Rightarrow  Hyperbola e=e = 1613\frac { 16 } { 13 } >1> 1 \Rightarrow Hyperbola

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