Use the Quadratic Formula to Solve For $y$ $x ^ { 2 } + x y + 4 y ^ { 2 } + x + y - 4 = 0$

Multiple Choice

Use the Quadratic Formula to solve for $y$ . $x ^ { 2 } + x y + 4 y ^ { 2 } + x + y - 4 = 0$

A) $y = \frac { ( x + 1 ) \pm \sqrt { ( x - 1 ) ^ { 2 } - 8 \left( x ^ { 2 } - x + 4 \right) } } { 4 }$
B) $y = \frac { - ( x + 1 ) \pm \sqrt { ( x + 1 ) ^ { 2 } - 8 \left( x ^ { 2 } + x + 4 \right) } } { 4 }$
C) $y = \frac { - ( x + 1 ) \pm \sqrt { ( x + 1 ) ^ { 2 } - 8 \left( x ^ { 2 } + x - 4 \right) } } { 4 }$
D) $y = \frac { ( x + 1 ) \pm \sqrt { ( x + 1 ) ^ { 2 } - 8 \left( x ^ { 2 } + x - 4 \right) } } { 4 }$
E) $y = \frac { - ( x + 1 ) \pm \sqrt { ( x + 1 ) ^ { 2 } + 8 \left( x ^ { 2 } + x - 4 \right) } } { 4 }$