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Find the Standard Form of the Equation of the Hyperbola (0,±6)( 0 , \pm 6 )

Question 348

Multiple Choice

Find the standard form of the equation of the hyperbola with the given characteristics and center at the origin.
Vertices: (0,±6) ( 0 , \pm 6 ) ; asymptotes: y=±6xy = \pm 6 x


A) y21x236=1\frac { y ^ { 2 } } { 1 } - \frac { x ^ { 2 } } { 36 } = 1
B) y236+x21=1\frac { y ^ { 2 } } { 36 } + \frac { x ^ { 2 } } { 1 } = 1
C) x236+y21=1\frac { x ^ { 2 } } { 36 } + \frac { y ^ { 2 } } { 1 } = 1
D) y236x21=1\frac { y ^ { 2 } } { 36 } - \frac { x ^ { 2 } } { 1 } = 1
E) x236y21=1\frac { x ^ { 2 } } { 36 } - \frac { y ^ { 2 } } { 1 } = 1

Correct Answer:

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