Select the graph of the polar equation using symmetry, zeros, maximum r-values, and any other additional points.

r = 4 + 6 \sin \theta

A)Symmetric with respect to

\theta = \frac { \pi } { 2 }

| r | = 10

when

\theta = \frac { \pi } { 2 }

r = 0

when

\theta = \frac { 7 \pi } { 6 } , \theta = \frac { 11 \pi } { 6 }

$Select the graph of the polar equation using symmetry, zeros, maximum r-values, and any other additional points. r = 4 + 6 \sin \theta A)Symmetric with respect to \theta = \frac { \pi } { 2 } | r | = 10 when \theta = \frac { \pi } { 2 } r = 0 when \theta = \frac { 7 \pi } { 6 } , \theta = \frac { 11 \pi } { 6 } B)Symmetric with respect to \theta = \frac { \pi } { 2 } | r | = 10 when \theta = \frac { \pi } { 2 } r = 0 when \theta = \frac { 7 \pi } { 6 } , \theta = \frac { 11 \pi } { 6 } C)Symmetric with respect to \theta = \frac { \pi } { 2 } | r | = 10 when \theta = \frac { \pi } { 2 } r = 0 when \theta = \frac { 7 \pi } { 6 } , \theta = \frac { 11 \pi } { 6 } D)Symmetric with respect to \theta = \frac { \pi } { 2 } | r | = 10 when \theta = \frac { \pi } { 2 } r = 0 when \theta = \frac { 7 \pi } { 6 } , \theta = \frac { 11 \pi } { 6 } E)Symmetric with respect to \theta = \frac { \pi } { 2 } | r | = 10 when \theta = \frac { \pi } { 2 } r = 0 when \theta = \frac { 7 \pi } { 6 } , \theta = \frac { 11 \pi } { 6 }$
B)Symmetric with respect to

\theta = \frac { \pi } { 2 }

| r | = 10

when

\theta = \frac { \pi } { 2 }

r = 0

when

\theta = \frac { 7 \pi } { 6 } , \theta = \frac { 11 \pi } { 6 }

\theta = \frac { \pi } { 2 }

| r | = 10

when

\theta = \frac { \pi } { 2 }

r = 0

when

\theta = \frac { 7 \pi } { 6 } , \theta = \frac { 11 \pi } { 6 }

\theta = \frac { \pi } { 2 }

| r | = 10

when

\theta = \frac { \pi } { 2 }

r = 0

when

\theta = \frac { 7 \pi } { 6 } , \theta = \frac { 11 \pi } { 6 }

\theta = \frac { \pi } { 2 }

| r | = 10

when

\theta = \frac { \pi } { 2 }

r = 0

when

\theta = \frac { 7 \pi } { 6 } , \theta = \frac { 11 \pi } { 6 }

Find the Center and Foci of the Hyperbola (y−8)29−(x+5)227=1\frac { ( y - 8 ) ^ { 2 } } { 9 } - \frac { ( x + 5 ) ^ { 2 } } { 27 } = 19(y−8)2​−27(x+5)2​=1

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Find the Center and Foci of the Hyperbola $\frac { ( y - 8 ) ^ { 2 } } { 9 } - \frac { ( x + 5 ) ^ { 2 } } { 27 } = 1$

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