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Find the Standard Form of the Equation of the Hyperbola 45\frac { 4 } { 5 }

Question 105

Multiple Choice

Find the standard form of the equation of the hyperbola with the given characteristics.
vertices: (-10, -2) , (0, -2)
Asymptotes: y = ± 45\frac { 4 } { 5 } x


A) (x+5) 225(y+2) 216=0\frac { ( x + 5 ) ^ { 2 } } { 25 } - \frac { ( y + 2 ) ^ { 2 } } { 16 } = 0
B) (x+5) 225+(y+2) 216=1\frac { ( x + 5 ) ^ { 2 } } { 25 } + \frac { ( y + 2 ) ^ { 2 } } { 16 } = 1
C) (y+5) 225(x+2) 216=1\frac { ( y + 5 ) ^ { 2 } } { 25 } - \frac { ( x + 2 ) ^ { 2 } } { 16 } = 1
D) (y2) 225(x+2) 216=1\frac { ( y - 2 ) ^ { 2 } } { 25 } - \frac { ( x + 2 ) ^ { 2 } } { 16 } = 1
E) (x+5) 225(y+2) 216=1\frac { ( x + 5 ) ^ { 2 } } { 25 } - \frac { ( y + 2 ) ^ { 2 } } { 16 } = 1

Correct Answer:

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