The Path of a Projectile Projected Horizontally with a Velocity $x ^ { 2 } = - \frac { v ^ { 2 } } { 16 } ( y - s )$

Multiple Choice

The path of a projectile projected horizontally with a velocity of v feet per second at a height of s feet, where the model for the path is $x ^ { 2 } = - \frac { v ^ { 2 } } { 16 } ( y - s )$ .In this model (in which air resistance is disregarded) , y is the height (in feet) of the projectile and x is the horizontal distance (in feet) the projectile travels.A ball is thrown from the top of a 150-foot tower with a velocity of 32 feet per second.Find the equation of the parabolic path.

A) $x ^ { 2 } = - 32 ( y - 150 )$
B) $x ^ { 2 } = 64 ( y - 150 )$
C) $x ^ { 2 } = 1406 ( y - 32 )$
D) $x ^ { 2 } = - 1406 ( y - 32 )$
E) $x ^ { 2 } = - 64 ( y - 150 )$