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Find the General Form of the Equation of the Plane n=2j+6k\mathbf { n } = - 2 \mathbf { j } + 6 \mathbf { k }

Question 64

Multiple Choice

Find the general form of the equation of the plane passing through the point and perpendicular to the specified vector or line.
Point: (0,0,0)
Perpendicular to: n=2j+6k\mathbf { n } = - 2 \mathbf { j } + 6 \mathbf { k }


A) x+2y+6z=0x + 2 y + 6 z = 0
B) 6y+2z=06 y + 2 z = 0
C) x2y+6z=0x - 2 y + 6 z = 0
D) 2y+6z=0- 2 y + 6 z = 0
E) 2y6z=0- 2 y - 6 z = 0

Correct Answer:

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