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Find the General Form of the Equation of the Plane (3,0,0)( 3,0,0 )

Question 220

Multiple Choice

Find the general form of the equation of the plane passing through the point and perpendicular to the specified vector or line.
Point: (3,0,0) ( 3,0,0 ) Perpendicular to: x=3t,y=26t,z=4+tx = 3 - t , y = 2 - 6 t , z = 4 + t


A) x6yz+3=0- x - 6 y - z + 3 = 0
B) x6y+z+3=0x - 6 y + z + 3 = 0
C) x+6y+z+3=0- x + 6 y + z + 3 = 0
D) x6y+z+3=0- x - 6 y + z + 3 = 0
E) x6yz3=0- x - 6 y - z - 3 = 0

Correct Answer:

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