Multiple Choice
Find the angle of intersection of the planes in degrees.Round to a tenth of a degree.
3x + 2y - 6z = -5
-6x + 3y + z = 1
A) 112.3°
B) 2.0°
C) -22.3°
D) 109.4°
E) 20.8°
Correct Answer:

Verified
Correct Answer:
Verified
Related Questions
Q190: Determine whether the planes are parallel,orthogonal,or neither.
Q191: Find a set of parametric equations
Q192: Find the general form of the
Q193: Find the magnitude of v.
Q194: Find the angle <span class="ql-formula"
Q196: Find the angle between the two planes
Q197: Find a unit vector in the
Q198: Find a set of symmetric equations
Q199: Use the triple scalar product to
Q200: Find a unit vector in the