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The Brakes on a Bicycle Are Applied by Using a Downward

Question 161

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The brakes on a bicycle are applied by using a downward force of p pounds on the pedal when the six-inch crank makes a angle with the horizontal.Vectors representing the position of the crank and the force are V=16(cos70jsin70k) \mathbf { V } = \frac { 1 } { 6 } \left( - \cos 70 ^ { \circ } \mathbf { j } - \sin 70 ^ { \circ } \mathbf { k } \right) and F=pk\mathbf { F } = - p \mathbf { k } respectively.The magnitude of the torque on the crank is given by V×F\| \mathbf { V } \times \mathbf { F } \| .Using the given information,write the torque T on the crank as a function of p.  The brakes on a bicycle are applied by using a downward force of p pounds on the pedal when the six-inch crank makes a angle with the horizontal.Vectors representing the position of the crank and the force are  \mathbf { V } = \frac { 1 } { 6 } \left( - \cos 70 ^ { \circ } \mathbf { j } - \sin 70 ^ { \circ } \mathbf { k } \right)   and  \mathbf { F } = - p \mathbf { k }  respectively.The magnitude of the torque on the crank is given by  \| \mathbf { V } \times \mathbf { F } \|  .Using the given information,write the torque T on the crank as a function of p.     A)   T = - \frac { p } { 5 } \sin 70 ^ { \circ }  B)   T = \frac { p } { 3 } \cos 70 ^ { \circ }  C)   T = - \frac { p } { 5 } \cos 70 ^ { \circ }  D)   T = \frac { 1 } { 5 } \cos 70 ^ { \circ }  E)   T = \frac { p } { 5 } \sin 70 ^ { \circ }


A) T=p5sin70T = - \frac { p } { 5 } \sin 70 ^ { \circ }
B) T=p3cos70T = \frac { p } { 3 } \cos 70 ^ { \circ }
C) T=p5cos70T = - \frac { p } { 5 } \cos 70 ^ { \circ }
D) T=15cos70T = \frac { 1 } { 5 } \cos 70 ^ { \circ }
E) T=p5sin70T = \frac { p } { 5 } \sin 70 ^ { \circ }

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