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Find the First Five Terms of the Sequence αn=n2n+2\alpha _ { n } = \frac { n } { 2 n + 2 }

Question 231

Multiple Choice

Find the first five terms of the sequence. αn=n2n+2\alpha _ { n } = \frac { n } { 2 n + 2 }


A) α1=4,α2=13,α3=38,α4=25,α5=512\alpha _ { 1 } = 4 , \alpha _ { 2 } = \frac { 1 } { 3 } , \alpha _ { 3 } = \frac { 3 } { 8 } , \alpha _ { 4 } = \frac { 2 } { 5 } , \alpha _ { 5 } = \frac { 5 } { 12 }
B) α1=4,α2=13,α3=83,α4=25,α5=512\alpha _ { 1 } = 4 , \alpha _ { 2 } = \frac { 1 } { 3 } , \alpha _ { 3 } = \frac { 8 } { 3 } , \alpha _ { 4 } = \frac { 2 } { 5 } , \alpha _ { 5 } = \frac { 5 } { 12 }
C) α1=4,α2=13,α3=38,α4=25,α5=125\alpha _ { 1 } = 4 , \alpha _ { 2 } = \frac { 1 } { 3 } , \alpha _ { 3 } = \frac { 3 } { 8 } , \alpha _ { 4 } = \frac { 2 } { 5 } , \alpha _ { 5 } = \frac { 12 } { 5 }
D) α1=14,α2=13,α3=38,α4=25,α5=512\alpha _ { 1 } = \frac { 1 } { 4 } , \alpha _ { 2 } = \frac { 1 } { 3 } , \alpha _ { 3 } = \frac { 3 } { 8 } , \alpha _ { 4 } = \frac { 2 } { 5 } , \alpha _ { 5 } = \frac { 5 } { 12 }
E) α1=14,α2=13,α3=83,α4=25,α5=125\alpha _ { 1 } = \frac { 1 } { 4 } , \alpha _ { 2 } = \frac { 1 } { 3 } , \alpha _ { 3 } = \frac { 8 } { 3 } , \alpha _ { 4 } = \frac { 2 } { 5 } , \alpha _ { 5 } = \frac { 12 } { 5 }

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