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Find the Limit (If It Exists) $\lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x }$

Question 174

Multiple Choice

Find the limit (if it exists) .Use a graphing utility to verify your result graphically. $\lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x }$

A) $\lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = - \frac { 1 } { 9 }$ $Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } A) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = - \frac { 1 } { 9 } B) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = \frac { 1 } { 9 } C) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = - \frac { 1 } { 12 } D) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = \frac { 1 } { 12 } E) does not exist$
B) $\lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = \frac { 1 } { 9 }$ $Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } A) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = - \frac { 1 } { 9 } B) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = \frac { 1 } { 9 } C) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = - \frac { 1 } { 12 } D) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = \frac { 1 } { 12 } E) does not exist$
C) $\lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = - \frac { 1 } { 12 }$ $Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } A) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = - \frac { 1 } { 9 } B) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = \frac { 1 } { 9 } C) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = - \frac { 1 } { 12 } D) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = \frac { 1 } { 12 } E) does not exist$
D) $\lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = \frac { 1 } { 12 }$ $Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } A) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = - \frac { 1 } { 9 } B) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = \frac { 1 } { 9 } C) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = - \frac { 1 } { 12 } D) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = \frac { 1 } { 12 } E) does not exist$
E) does not exist $Find the limit (if it exists) .Use a graphing utility to verify your result graphically. \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } A) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = - \frac { 1 } { 9 } B) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = \frac { 1 } { 9 } C) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = - \frac { 1 } { 12 } D) \lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x } = \frac { 1 } { 12 } E) does not exist$

Find the Limit (If It Exists) lim⁡x→03sec⁡xtan⁡x\lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x }limx→0​tanx3secx​

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Find the Limit (If It Exists) $\lim _ { x \rightarrow 0 } \frac { 3 \sec x } { \tan x }$

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