Solved

TABLE 16-11
Business Closures in Laramie, Wyoming from 1989 to 1994

Question 52

Short Answer

TABLE 16-11
Business closures in Laramie, Wyoming from 1989 to 1994 were:
199310199411199513199619199724199835\begin{array} { l l } 1993 & 10 \\1994 & 11 \\1995 & 13 \\1996 & 19 \\1997 & 24 \\1998 & 35\end{array} Microsoft Excel was used to fit both first-order and second-order autoregressive models, resulting in the following partial outputs:
SUMMARY OUTPUT- 2nd  Order ModelCoefficients Intercept 5.77 XVariable 1 0.80 XVariable 2 1.14SUMMARY OUTPUT- 1st Order ModelCoefficientsIntercept 4.16XVariable 1 1.59\begin{array} { |l c |}\hline\text {SUMMARY OUTPUT- \(2 ^ { \text {nd } }\) Order Model}\\& \text {Coefficients}\\ \text { Intercept } & - 5.77 \\ \text { XVariable 1 } & 0.80 \\ \text { XVariable 2 } & 1.14\\\\ \text {SUMMARY OUTPUT- 1st Order Model}\\& \text {Coefficients}\\ \text {Intercept }&- 4.16\\ \text {XVariable 1 }& 1.59\\\hline \end{array}

-Referring to Table 16-11, the residuals for the second-order autoregressive model are____, ____,____ , and _____.

Correct Answer:

verifed

Verified

-1.43, 1.8...

View Answer

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions