TABLE 12-19
An agronomist wants to compare the crop yield of 3 varieties of chickpea seeds. She plants all 3 varieties of the seeds on each of 5 different patches of fields. She then measures the crop yield in bushels per acre. Treating this as a randomized block design, the results are presented in the table that follows.

\begin{array} { l l l l } \text { Fields } & \text { Smith } & \text { Walsh } & \text { Trevor } \\1 & 11.1 & 19.0 & 14.6 \\2 & 13.5 & 18.0 & 15.7 \\3 & 15.3 & 19.8 & 16.8 \\4 & 14.6 & 19.6 & 16.7 \\5 & 9.8 & 16.6 & 15.2\end{array}

Below is the Minitab output of the Friedman rank test:
Friedman Test: Yield versus Varieties, Fields

Friedman test for Yield byVarieties blocked by Fields

\mathrm{s}=

10.00

\quad

\mathrm{DF}=2 \quad \mathrm{P}=0.007

\begin{array}{llcc} & \text { Est } & \text { Sum of } \\ \text { Varieties } & \text { N } & \text { Median } & \text { Ranks } \\ \text { Smith } & 5 & 13.500 & 5.0 \\ \text { Trevor } & 5 & 15.667 & 10.0 \\ \text { Walsh } & 5 & 18.533 & 15.0 \\\\ \text { Grand median= } & 15.900\end{array}

-Referring to Table 12-19, the null hypothesis for the Friedman rank test for the difference in the means should be rejected at a 0.01 level of significance.

If We Use the ?2 Method of Analysis to Test

Multiple Choice

Correct Answer:VerifiedUnlock this answer nowGet Access to more Verified Answers free of chargeAccess For Free

If We Use the ?² Method of Analysis to Test

Correct Answer:
Verified
Unlock this answer now
Get Access to more Verified Answers free of charge