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TABLE 11-3
a Realtor Wants to Compare the Average Sales-To-Appraisal 1.2,1.1,0.9,0.4 \quad 1.2,1.1,0.9,0.4 \quad

Question 120

Multiple Choice

TABLE 11-3
A realtor wants to compare the average sales-to-appraisal ratios of residential properties sold in four neighborhoods (A, B, C, and D) . Four properties are randomly selected from each neighborhood and the ratios recorded for each, as shown below.
A: 1.2,1.1,0.9,0.4 \quad 1.2,1.1,0.9,0.4 \quad C: 1.0,1.5,1.1,1.3 \quad 1.0,1.5,1.1,1.3
B: 2.5,2.1,1.9,1.6\quad 2.5,2.1,1.9,1.6 \quad D: 0.8,1.3,1.1,0.7 \quad 0.8,1.3,1.1,0.7

Interpret the results of the analysis summarized in the following table:
 Source  df  SS  MS  F  PR > F  Neighborhoods 3.18191.060610.760.001 Error 12 Total 4.3644\begin{array}{llllll}\text { Source } & \text { df } & \text { SS } & \text { MS } & \text { F } & \text { PR }>\text { F } \\\text { Neighborhoods } & & 3.1819& 1.0606 & 10.76 & 0.001 & & \\\text { Error } & 12 & & & & \\\text { Total } & & 4.3644 & &\end{array}

-Referring to Table 11-3, what is the null hypothesis for Levene's test for homogeneity of variances?


A) H0:πA=πB=πC=πD H_{0}: \pi_{A}=\pi_{B}=\pi_{C}=\pi_{D}

B) H0 : MA = MB = MC = MD

C) H0:σA2=σB2=σC2=σD2 H_{0}: \sigma_{A}^{2}=\sigma_{B}^{2}=\sigma_{C}^{2}=\sigma_{D}^{2}

D) H0 : µA = µB = µC = µD

Correct Answer:

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