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The Variance Of xˉ1xˉ2\bar { x } _ { 1 } - \bar { x } _ { 2 }

Question 161

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The variance of xˉ1xˉ2\bar { x } _ { 1 } - \bar { x } _ { 2 } is V(xˉ1xˉ2)=σ12n1σ22n2V \left( \bar { x } _ { 1 } - \bar { x } _ { 2 } \right) = \frac { \sigma _ { 1 } ^ { 2 } } { n _ { 1 } } - \frac { \sigma _ { 2 } ^ { 2 } } { n _ { 2 } } .

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