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Suppose a Box Contains 2 Defective Transistors and 12 Good

Question 80

Multiple Choice

Suppose a box contains 2 defective transistors and 12 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that the first transistor is good G and the second transistor is defective D? ​


A) Pr(G first ∩ D second) = Suppose a box contains 2 defective transistors and 12 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that the first transistor is good G and the second transistor is defective D? ​ A) Pr(G first ∩ D second) = B) Pr(G first ∩ D second) = C) Pr(G first ∩ D second) = D) Pr(G first ∩ D second) = E) Pr(G first ∩ D second) =
B) Pr(G first ∩ D second) = Suppose a box contains 2 defective transistors and 12 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that the first transistor is good G and the second transistor is defective D? ​ A) Pr(G first ∩ D second) = B) Pr(G first ∩ D second) = C) Pr(G first ∩ D second) = D) Pr(G first ∩ D second) = E) Pr(G first ∩ D second) =
C) Pr(G first ∩ D second) = Suppose a box contains 2 defective transistors and 12 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that the first transistor is good G and the second transistor is defective D? ​ A) Pr(G first ∩ D second) = B) Pr(G first ∩ D second) = C) Pr(G first ∩ D second) = D) Pr(G first ∩ D second) = E) Pr(G first ∩ D second) =
D) Pr(G first ∩ D second) = Suppose a box contains 2 defective transistors and 12 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that the first transistor is good G and the second transistor is defective D? ​ A) Pr(G first ∩ D second) = B) Pr(G first ∩ D second) = C) Pr(G first ∩ D second) = D) Pr(G first ∩ D second) = E) Pr(G first ∩ D second) =
E) Pr(G first ∩ D second) = Suppose a box contains 2 defective transistors and 12 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that the first transistor is good G and the second transistor is defective D? ​ A) Pr(G first ∩ D second) = B) Pr(G first ∩ D second) = C) Pr(G first ∩ D second) = D) Pr(G first ∩ D second) = E) Pr(G first ∩ D second) =

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