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Suppose a Box Contains 6 Defective Transistors and 13 Good

Question 47

Multiple Choice

Suppose a box contains 6 defective transistors and 13 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that one of the transistors drawn is good G and one of them is defective D? ​


A) Pr(one G ∩ one D) = Suppose a box contains 6 defective transistors and 13 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that one of the transistors drawn is good G and one of them is defective D? ​ A) Pr(one G ∩ one D)  =   B) Pr(one G ∩ one D)  =   C) Pr(one G ∩ one D)  =   D) Pr(one G ∩ one D)  =   E) Pr(one G ∩ one D)  =
B) Pr(one G ∩ one D) = Suppose a box contains 6 defective transistors and 13 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that one of the transistors drawn is good G and one of them is defective D? ​ A) Pr(one G ∩ one D)  =   B) Pr(one G ∩ one D)  =   C) Pr(one G ∩ one D)  =   D) Pr(one G ∩ one D)  =   E) Pr(one G ∩ one D)  =
C) Pr(one G ∩ one D) = Suppose a box contains 6 defective transistors and 13 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that one of the transistors drawn is good G and one of them is defective D? ​ A) Pr(one G ∩ one D)  =   B) Pr(one G ∩ one D)  =   C) Pr(one G ∩ one D)  =   D) Pr(one G ∩ one D)  =   E) Pr(one G ∩ one D)  =
D) Pr(one G ∩ one D) = Suppose a box contains 6 defective transistors and 13 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that one of the transistors drawn is good G and one of them is defective D? ​ A) Pr(one G ∩ one D)  =   B) Pr(one G ∩ one D)  =   C) Pr(one G ∩ one D)  =   D) Pr(one G ∩ one D)  =   E) Pr(one G ∩ one D)  =
E) Pr(one G ∩ one D) = Suppose a box contains 6 defective transistors and 13 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that one of the transistors drawn is good G and one of them is defective D? ​ A) Pr(one G ∩ one D)  =   B) Pr(one G ∩ one D)  =   C) Pr(one G ∩ one D)  =   D) Pr(one G ∩ one D)  =   E) Pr(one G ∩ one D)  =

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