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The Model  distance ^=3.30+0.235 \sqrt{\hat{\text { distance }}}=3.30+0.235 (Speed) Can Be Used to Predict the Stopping Distance (In

Question 105

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The model  distance ^=3.30+0.235 \sqrt{\hat{\text { distance }}}=3.30+0.235 (speed) can be used to predict the stopping distance (in feet) for a car traveling at a specific speed (in mph) . According to this model, about how much distance will a car going 65mph 65 \mathrm{mph} need to stop?


A) 4.3 feet
B) 729.0 feet
C) 18.6 feet
D) 27.0 feet
E) 345.0 feet

Correct Answer:

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