If an X-Ray with a Wavelength of 154 Pm Is $\theta$

Multiple Choice

If an X-ray with a wavelength of 154 pm is diffracted at an angle 2 $\theta$ = 14.6°, according to the Bragg equation (n $\lambda$ = 2 d sin $\theta$ ) , what is the distance between layers of the crystal that give rise to this diffraction? Assume n = 1 in this problem.

A) 610.9 pm
B) 305.5 pm
C) 606.0 pm
D) 1212 pm
E) 198.1 pm