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Find an Equation of the Tangent Line to the Graph f(x)=2xf ( x ) = 2 \sqrt { x }

Question 97

Multiple Choice

Find an equation of the tangent line to the graph of the function f(x) =2xf ( x ) = 2 \sqrt { x } at the point that has x-coordinate x=36x = 36 . [Hint: use point-slope formula to find the equation of the tangent line.]


A) y=x66y = - \frac { x } { 6 } - 6
B) y=x6+6y = \frac { x } { 6 } + 6
C) y=6x+6y = 6 x + 6
D) y=6x+16y = 6 x + \frac { 1 } { 6 }
E) y=x36+6y = \frac { x } { 36 } + 6

Correct Answer:

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