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In Calculating 95% Confidence Interval For μ1μ2;\mu _ { 1 } - \mu _ { 2 } ;

Question 12

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In calculating 95% confidence interval for μ1μ2;\mu _ { 1 } - \mu _ { 2 } ; the difference between the means of two normally distributed populations, summary statistics from two independent samples are: m=10,xˉ=50,s12=.64,n=10,yˉ=40, and s22=1.86m = 10 , \bar { x } = 50 , s _ { 1 } ^ { 2 } = .64 , n = 10 , \bar { y } = 40 \text {, and } s _ { 2 } ^ { 2 } = 1.86 Then, the upper limit of the confidence interval is


A) 10.953
B) 9.047
C) 9.216
D) 10.784
E) 10.0

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