The Upper Limit of a 95% Confidence Interval for the Variance

Multiple Choice

The upper limit of a 95% confidence interval for the variance $\sigma ^ { 2 }$ of a normal population using a sample of size n and variance value $s ^ { 2 }$ is given by:

A) $( n - 1 ) s ^ { 2 } / \chi _ { .05 , { n - 1 } } ^ { 2 }$
B) $( n - 1 ) s ^ { 2 } / \chi _ { .015 , n - 1 } ^ { 2 }$
C) $( n - 1 ) s ^ { 2 } / \chi _ {.95 ,{ n - 1 } } ^ { 2 }$
D) $( n - 1 ) s ^ { 2 } / \chi ^ { 2 } _{.975 , n - 1}$
E) None of the above answers are correct.