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The 95 Percent Confidence Interval for a Population Mean Is $\bar { X } - \left( t _ { .01 } \right) ( s \bar { X } )$

Question 68

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The 95 percent confidence interval for a population mean is given by. $The 95 percent confidence interval for a population mean is given by. A) \bar { X } - \left( t _ { .01 } \right) ( s \bar { X } ) to \bar { X } + \left( t _ { .01 } \right) ( s \bar { X } ) B) \bar { X } - \left( \operatorname { t.g5 } ^ { .95 } \right) \left( s _ { X } \right) to \bar { X } + \left( t _ { .95 } \right) \left( s _ { X } \right) C) \bar { X } - \left( t _ { 05 } \right) \left( s ^ { \prime } \right) to \bar { X } + \left( t _ { 05 } \right) \left( s _ { X } \right) D) \bar { X } - \left( t _ { .05 } \right) ( s ) to \bar { X } + \left( t _ { .05 } \right) ( s )$ $The 95 percent confidence interval for a population mean is given by. A) \bar { X } - \left( t _ { .01 } \right) ( s \bar { X } ) to \bar { X } + \left( t _ { .01 } \right) ( s \bar { X } ) B) \bar { X } - \left( \operatorname { t.g5 } ^ { .95 } \right) \left( s _ { X } \right) to \bar { X } + \left( t _ { .95 } \right) \left( s _ { X } \right) C) \bar { X } - \left( t _ { 05 } \right) \left( s ^ { \prime } \right) to \bar { X } + \left( t _ { 05 } \right) \left( s _ { X } \right) D) \bar { X } - \left( t _ { .05 } \right) ( s ) to \bar { X } + \left( t _ { .05 } \right) ( s )$ $The 95 percent confidence interval for a population mean is given by. A) \bar { X } - \left( t _ { .01 } \right) ( s \bar { X } ) to \bar { X } + \left( t _ { .01 } \right) ( s \bar { X } ) B) \bar { X } - \left( \operatorname { t.g5 } ^ { .95 } \right) \left( s _ { X } \right) to \bar { X } + \left( t _ { .95 } \right) \left( s _ { X } \right) C) \bar { X } - \left( t _ { 05 } \right) \left( s ^ { \prime } \right) to \bar { X } + \left( t _ { 05 } \right) \left( s _ { X } \right) D) \bar { X } - \left( t _ { .05 } \right) ( s ) to \bar { X } + \left( t _ { .05 } \right) ( s )$ $The 95 percent confidence interval for a population mean is given by. A) \bar { X } - \left( t _ { .01 } \right) ( s \bar { X } ) to \bar { X } + \left( t _ { .01 } \right) ( s \bar { X } ) B) \bar { X } - \left( \operatorname { t.g5 } ^ { .95 } \right) \left( s _ { X } \right) to \bar { X } + \left( t _ { .95 } \right) \left( s _ { X } \right) C) \bar { X } - \left( t _ { 05 } \right) \left( s ^ { \prime } \right) to \bar { X } + \left( t _ { 05 } \right) \left( s _ { X } \right) D) \bar { X } - \left( t _ { .05 } \right) ( s ) to \bar { X } + \left( t _ { .05 } \right) ( s )$

A) $\bar { X } - \left( t _ { .01 } \right) ( s \bar { X } )$ to $\bar { X } + \left( t _ { .01 } \right) ( s \bar { X } )$
B) $\bar { X } - \left( \operatorname { t.g5 } ^ { .95 } \right) \left( s _ { X } \right)$ to $\bar { X } + \left( t _ { .95 } \right) \left( s _ { X } \right)$
C) $\bar { X } - \left( t _ { 05 } \right) \left( s ^ { \prime } \right)$ to $\bar { X } + \left( t _ { 05 } \right) \left( s _ { X } \right)$
D) $\bar { X } - \left( t _ { .05 } \right) ( s )$ to $\bar { X } + \left( t _ { .05 } \right) ( s )$

The 95 Percent Confidence Interval for a Population Mean Is Xˉ−(t.01)(sXˉ)\bar { X } - \left( t _ { .01 } \right) ( s \bar { X } )Xˉ−(t.01​)(sXˉ)

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The 95 Percent Confidence Interval for a Population Mean Is $\bar { X } - \left( t _ { .01 } \right) ( s \bar { X } )$

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