In Testing Whether the Means of Two Normal Populations Are $\bar { x } _ { 1 }$

Short Answer

In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows: n₁ = 25, $\bar { x } _ { 1 }$ = 7.30, s₁ = 1.05.
N₂ = 30, $\bar { x } _ { 2 }$ = 6.80, s₂ = 1.20.
Assume that the population variances are equal. Then the standard error of the sampling distribution of the sample mean difference $\bar { x } _ { 1 } - \bar { x } _ { 2 }$ is equal to: $\begin{array}{|l|l|}\hline\text { A. } & 0.3072 . \\\hline \text { B. } & 0.0917 . \\\hline \text { C. } & 0.3028 \\\hline \text { D. } & 0.0944 . \\\hline\end{array}$